Semiconducting Devices Question 275
Question: For a given triode $ \mu =20 $ . The load resistance is 1.5 times the anode resistance. The maximum gain will be
[CPMT 1992]
Options:
A) 16
B) 12
C) 10
D) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
Voltage gain $ A _{v}=\frac{\mu }{1+\frac{r _{p}}{R _{L}}} $
$ \because R _{L}=1.5r _{p} $
$ \Rightarrow A _{v}=\frac{\mu }{1+\frac{r _{p}}{1.5r _{p}}}=\frac{3}{5}\mu $
$ =\frac{3}{5}\times 20=12 $ .
