Semiconducting Devices Question 275

Question: For a given triode $ \mu =20 $ . The load resistance is 1.5 times the anode resistance. The maximum gain will be

[CPMT 1992]

Options:

A) 16

B) 12

C) 10

D) None of the above

Show Answer

Answer:

Correct Answer: B

Solution:

Voltage gain $ A _{v}=\frac{\mu }{1+\frac{r _{p}}{R _{L}}} $

$ \because R _{L}=1.5r _{p} $
$ \Rightarrow A _{v}=\frac{\mu }{1+\frac{r _{p}}{1.5r _{p}}}=\frac{3}{5}\mu $

$ =\frac{3}{5}\times 20=12 $ .



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