Semiconducting Devices Question 258
Question: Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $ 2.54{AA} $ . The value of the lattice constant for this lattice is
[CBSE PMT 2005]
Options:
A) $ 1.27{AA} $
B) $ 5.08{AA} $
C) $ 2.54{AA} $
D) $ 3.59{AA} $
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Answer:
Correct Answer: D
Solution:
$ \sqrt{2}a=4r $
Therefore $ a=\frac{4r}{\sqrt{2}}=\sqrt{2}(2r)=\sqrt{2}\times 2.54=3.59{AA} $