Semiconducting Devices Question 258

Question: Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $ 2.54{AA} $ . The value of the lattice constant for this lattice is

[CBSE PMT 2005]

Options:

A) $ 1.27{AA} $

B) $ 5.08{AA} $

C) $ 2.54{AA} $

D) $ 3.59{AA} $

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Answer:

Correct Answer: D

Solution:

$ \sqrt{2}a=4r $

Therefore $ a=\frac{4r}{\sqrt{2}}=\sqrt{2}(2r)=\sqrt{2}\times 2.54=3.59{AA} $



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