Semiconducting Devices Question 255
Question: The nearest distance between two atoms in case of a bcc lattice is equal to
[J & K CET 2004]
Options:
A) $ a\frac{\sqrt{2}}{3} $
B) $ a\frac{\sqrt{3}}{2} $
C) $ q\sqrt{3} $
D) $ \frac{a}{\sqrt{2}} $
Show Answer
Answer:
Correct Answer: B
Solution:
The nearest distance between two atoms in a bcc lattice = 2 (atomic radius) $ =2\times ( \frac{\sqrt{3}a}{4} )=\frac{\sqrt{3}a}{2} $
