Semiconducting Devices Question 252
Question: The distance between the body centred atom and a corner atom in sodium $ (a=4.225{AA}) $ is
[CBSE PMT 1995]
Options:
A) $ 3.66{AA} $
B) $ 3.17{AA} $
C) $ 2.99{AA} $
D) $ 2.54{AA} $
Show Answer
Answer:
Correct Answer: A
Solution:
Sodium has bcc structure.
The distance between body centre and a corner $ =\frac{\sqrt{3}a}{2} $
$ =\frac{\sqrt{3}\times 4.225}{2}=3.66{AA} $
