Semiconducting Devices Question 252

Question: The distance between the body centred atom and a corner atom in sodium $ (a=4.225{AA}) $ is

[CBSE PMT 1995]

Options:

A) $ 3.66{AA} $

B) $ 3.17{AA} $

C) $ 2.99{AA} $

D) $ 2.54{AA} $

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Answer:

Correct Answer: A

Solution:

Sodium has bcc structure.

The distance between body centre and a corner $ =\frac{\sqrt{3}a}{2} $

$ =\frac{\sqrt{3}\times 4.225}{2}=3.66{AA} $



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