SATHEE: Semiconducting Devices Question 252

Semiconducting Devices Question 252

Question: The distance between the body centred atom and a corner atom in sodium $(a = 4.225 A A)$ is

[CBSE PMT 1995]

Options:

A) $3.66 A A$

B) $3.17 A A$

C) $2.99 A A$

D) $2.54 A A$

Show Answer

Answer:

Correct Answer: A

Solution:

Sodium has bcc structure.

The distance between body centre and a corner $= \frac{\sqrt{3} a}{2}$

$= \frac{\sqrt{3} \times 4.225}{2} = 3.66 A A$

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Semiconducting Devices Question 252

Question: The distance between the body centred atom and a corner atom in sodium (a=4.225AA) is

Options:

Answer:

Solution:

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Question: The distance between the body centred atom and a corner atom in sodium $(a = 4.225 A A)$ is