Semiconducting Devices Question 206

Question: The approximate ratio of resistances in the forward and reverse bias of the PN-junction diode is

[MP PET 2000; MP PMT 1999, 2002, 03; Pb. PMT 2003]

Options:

A) $ 10^{2}:1 $

B) $ {{10}^{-2}}:1 $

C) $ 1:{{10}^{-4}} $

D) $ 1:10^{4} $

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Answer:

Correct Answer: D

Solution:

Resistance in forward biasing $ R _{fr}\approx 10\Omega $ and resistance in reverse biasing $ R _{Rw}\approx 10^{5}\Omega $

Therefore $ \frac{R _{fr}}{R _{Rw}}=\frac{1}{10^{4}} $



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