Semiconducting Devices Question 206
Question: The approximate ratio of resistances in the forward and reverse bias of the PN-junction diode is
[MP PET 2000; MP PMT 1999, 2002, 03; Pb. PMT 2003]
Options:
A) $ 10^{2}:1 $
B) $ {{10}^{-2}}:1 $
C) $ 1:{{10}^{-4}} $
D) $ 1:10^{4} $
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Answer:
Correct Answer: D
Solution:
Resistance in forward biasing $ R _{fr}\approx 10\Omega $ and resistance in reverse biasing $ R _{Rw}\approx 10^{5}\Omega $
Therefore $ \frac{R _{fr}}{R _{Rw}}=\frac{1}{10^{4}} $