Semiconducting Devices Question 119
Question: In a transistor in CE configuration, the ratio of power gain to voltage gain is
[J & K CET 2005]
Options:
A) a
B) b / a
C) ba
D) b
Show Answer
Answer:
Correct Answer: D
Solution:
For CE configuration voltage gain $ =\beta \times R _{L}/R _{i} $
Power gain $ ={{\beta }^{2}}\times R _{L}/R _{i} $
Therefore $ \frac{\text{Power gain}}{\text{Voltage gain}}=\beta $
