Properties Of Solids And Liquids Question 94
Question: A glass flask is filled up to a mark with 50 cc of mercury at 18ºC. If the flask and contents are heated to 38ºC, how much mercury will be above the mark? (a for glass is 9 × 10?6/ºC and coefficient of real expansion of mercury is 180 × 10?6/ºC) [EAMCET 1997]
Options:
A) 0.85 cc
B) 0.46 cc
C) 0.153 cc
D) 0.05 cc
Show Answer
Answer:
Correct Answer: C
Solution:
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by
$ \Delta V=V _{0}[{\gamma _{L}}-{\gamma _{g}}]\Delta \theta =V[{\gamma _{m}}-3{\alpha _{g}}]\Delta \theta $
$ =50 [180\times {{10}^{-6}}-3\times 9\times {{10}^{-6}}](38-18)=0.153cc $
