Properties Of Solids And Liquids Question 83
Question: 300 gm of water at 25°C is added to 100 gm of ice at 0°C. The final temperature of the mixture is [MP PET 2004]
Options:
A) $ -\frac{5}{3}{}^\circ C $
B) $ -\frac{5}{2}{}^\circ C $
C) ? 5°C
D) 0°C
Show Answer
Answer:
Correct Answer: D
Solution:
$ {\theta _{\text{mix}}}=\frac{m _{W}{\theta _{W}}-\frac{{m _{i}}{L _{i}}}{S _{W}}}{{m _{i}}+m _{W}} $
$ =\frac{300\times 25-\frac{100\times 80}{1}}{100+300}=-{{1.25}^{o}}C $
Which is not possible. Hence $ {\theta _{mix}}=0^{o}C $
