Properties Of Solids And Liquids Question 72
Question: One kilogram of ice at 0°C is mixed with one kilogram of water at 80°C. The final temperature of the mixture is (Take : specific heat of water$ =4200Jk{{g}^{-1}}{{K}^{-1}} $ , latent heat of ice $ =336kJk{{g}^{-1}}) $ [KCET 2002]
Options:
A) 40°C
B) 60°C
C) 0°C
D) 50°C
Show Answer
Answer:
Correct Answer: C
Solution:
$ {\theta _{\text{mix}}}=\frac{m _{W}{\theta _{W}}-\frac{{m _{i}}{L _{i}}}{c _{W}}}{{m _{i}}+m _{W}} $
$ \because m _{i}=m _{W} $ therefore$ {\theta _{mix}}=\frac{{\theta _{W}}-\frac{L _{i}}{c _{W}}}{2} $
$ =\frac{80+0-\frac{336}{4.2}}{2}=0{}^\circ C $
