Properties Of Solids And Liquids Question 599
Question: A hammer of mass 1kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is 0.105 cal/gm$ {}^\circ C $ and half the energy is converted into heat, the raise in temperature of nail is
Options:
A) $ 7.1{}^\circ C $
B) $ 9.2{}^\circ C $
C) $ 10.5{}^\circ C $
D) $ 12.1{}^\circ C $
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Answer:
Correct Answer: A
Solution:
$ W=JQ $
$ \Rightarrow $ $ \frac{1}{2}( \frac{1}{2}Mv^{2} )=J(m.c.\Delta \theta ) $
$ \Rightarrow $ $ \frac{1}{4}\times 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ] $
$ \Rightarrow $ $ \Delta \theta =7.1{}^\circ C $
