Properties Of Solids And Liquids Question 564

Question: 2 kg of ice at $ 20{}^\circ C $ is mixed with 5kg of water at $ 20{}^\circ C $ in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are $ 1kcal/kg/{}^\circ C $ and $ 0.5kcal/kg/{}^\circ C $ while the latent heat of fusion of ice is 80 kcal/kg

Options:

A) 7kg

B) 6kg

C) 4kg

D) 2kg

Show Answer

Answer:

Correct Answer: B

Solution:

Initially ice will absorb heat to raise its temperature to $ 0{}^\circ C $ then it’s melting takes place

If $ m _{1} $ = Initial mass of ice, $ m _{2} $ ’ = Mass of ice that melts and $ m _{W} $ = Initial mass of water

By Law of mixture

Heat gained by ice = Heat lost by water

$ \Rightarrow m _{1}\times ( 20 )+m _{1}’\times L=m _{W}c _{W}[ 20 ] $

$ \Rightarrow 2\times 0.5( 20 )+m _{1}’\times 80=5\times I\times 20 $

$ \Rightarrow {{\text{m}} _{\text{1}}}’\text{ =1kg} $

So, final mass of water = Initial mass of water + Mass of

Ice that melts = 5 +1 = 6kg



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