SATHEE: Properties Of Solids And Liquids Question 564

Properties Of Solids And Liquids Question 564

Question: 2 kg of ice at $20^{\circ} C$ is mixed with 5kg of water at $20^{\circ} C$ in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water and ice are $1 k c a l / k g /^{\circ} C$ and $0.5 k c a l / k g /^{\circ} C$ while the latent heat of fusion of ice is 80 kcal/kg

Options:

A) 7kg

B) 6kg

C) 4kg

D) 2kg

Show Answer

Answer:

Correct Answer: B

Solution:

Initially ice will absorb heat to raise its temperature to $0^{\circ} C$ then it’s melting takes place

If $m_{1}$ = Initial mass of ice, $m_{2}$ ’ = Mass of ice that melts and $m_{W}$ = Initial mass of water

By Law of mixture

Heat gained by ice = Heat lost by water

$\Rightarrow m_{1} \times (20) + m_{1}^{'} \times L = m_{W} c_{W} [20]$

$\Rightarrow 2 \times 0.5 (20) + m_{1}^{'} \times 80 = 5 \times I \times 20$

$\Rightarrow {m_{1}}^{'} =1kg$

So, final mass of water = Initial mass of water + Mass of

Ice that melts = 5 +1 = 6kg

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अगला

Properties Of Solids And Liquids Question 564

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Properties Of Solids And Liquids Question 564

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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