Properties Of Solids And Liquids Question 551

Question: A steel scale is calibrated for$ \text{27}{{}^{\text{o}}}\text{C}\text{.} $ The error in a reading of 50 cm at$ 30{{}^{\text{o}}}\text{C} $ is $ [{\alpha _{steel}}=1.2\times {{10}^{-5}}/{{}^{o}}C] $

Options:

A) 0.018 mm

B) 0.18 mm

C) 0.0018 mm

D) 0.16 mm

Show Answer

Answer:

Correct Answer: A

Solution:

Error, $ \Delta L=L\alpha \Delta T=50\times 1.2\times {{10}^{-5}}\times 3 $ =0.018 mm



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