Properties Of Solids And Liquids Question 551
Question: A steel scale is calibrated for$ \text{27}{{}^{\text{o}}}\text{C}\text{.} $ The error in a reading of 50 cm at$ 30{{}^{\text{o}}}\text{C} $ is $ [{\alpha _{steel}}=1.2\times {{10}^{-5}}/{{}^{o}}C] $
Options:
A) 0.018 mm
B) 0.18 mm
C) 0.0018 mm
D) 0.16 mm
Show Answer
Answer:
Correct Answer: A
Solution:
Error, $ \Delta L=L\alpha \Delta T=50\times 1.2\times {{10}^{-5}}\times 3 $ =0.018 mm
