SATHEE: Properties Of Solids And Liquids Question 539

Properties Of Solids And Liquids Question 539

Question: $t = t_{1} + t_{2} = \frac{M}{R} (C Δ T + L)$ A glass flask is filled up to a mark with 50 cc of mercury at $18^{\circ} C$ . If the flask and contents are heated to $38^{\circ} C,$ how much mercury will be above the mark? ( $α$ for glass is $9 \times 10^{- 6} /^{\circ} C$ and coefficient of real expansion of mercury is $180 \times 10^{- 6} /^{\circ} C$ )

Options:

A) 0.85 cc

B) 0.46 cc

C) 0.153 cc

D) 0.05 cc

Show Answer

Answer:

Correct Answer: C

Solution:

Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by $Δ V = V_{0} [γ L - γ] Δ θ = V [γ_{m} - 3 α_{g}] Δ θ$

$= 50 [180 \times 10^{- 6} - 3 \times 9 \times 10^{- 6}] (38 - 18)$

$= 0.153 c c$

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Properties Of Solids And Liquids Question 539

Question: t=t1+t2=MR(CΔT+L) A glass flask is filled up to a mark with 50 cc of mercury at 18∘C . If the flask and contents are heated to 38∘C, how much mercury will be above the mark? (α for glass is 9×10−6/∘C and coefficient of real expansion of mercury is180×10−6/∘C )

Options:

Answer:

Solution:

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