Properties Of Solids And Liquids Question 539
Question: $ t=t _{1}+t _{2}=\frac{M}{R}(C\Delta T+L) $ A glass flask is filled up to a mark with 50 cc of mercury at $ 18{}^\circ C $ . If the flask and contents are heated to $ 38{}^\circ C, $ how much mercury will be above the mark? ($ \alpha $ for glass is $ 9\times {{10}^{-6}}/{}^\circ C $ and coefficient of real expansion of mercury is$ 180\times {{10}^{-6}}/{}^\circ C $ )
Options:
A) 0.85 cc
B) 0.46 cc
C) 0.153 cc
D) 0.05 cc
Show Answer
Answer:
Correct Answer: C
Solution:
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by $ \Delta V=V _{0}[ \gamma L-\gamma ]\Delta \theta\text{ = V}[ {\gamma _{m}}-3{\alpha _{g}} ]\Delta \theta $
$ =50 [ 180\times {{10}^{-6}}-3\times 9\times {{10}^{-6}} ]( 38-18 ) $
$ =0.153cc $
