Properties Of Solids And Liquids Question 470

Question: A bar of iron is 10 cm at 20°C. At 19°C it will be (a of iron = 11 ´ 10?6/°C) [EAMCET 1997]

Options:

A) 11 ´ 10?6 cm longer

B) 11 ´ 10?6 cm shorter

C) 11 ´ 10?5 cm shorter

D) 11 ´ 10?5 cm longer

Show Answer

Answer:

Correct Answer: C

Solution:

L=L0(1+αΔθ)

therefore L1L2=1+α(Δθ)11+α(Δθ)2

therefore 10L2=1+11×106×201+11×106×19

therefore L2=9.99989

therefore Length is shorten by 109.99989=0.00011=11×105cm



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