Properties Of Solids And Liquids Question 454

Question: A container contains hot water at $ 100{}^\circ C $ . If in time $ T _{1} $ temperature falls to $ 80{}^\circ C $ and the time $ T _{2} $ temperature falls to $ 60{}^\circ C $ form $ 80{}^\circ C $ , then

Options:

A) $ T _{1}=T _{2} $

B) $ T _{1}>T _{2} $

C) $ T _{1}<T _{2} $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Rate of coiling$ =\frac{-d\theta }{dt}\propto ( \frac{{\theta _{1}}+{\theta _{2}}}{2}-{\theta _{0}} ) $ In second case average temperature will be less hence rate of coiling will be less. Therefore time taken will be more than 4 minutes.



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