SATHEE: Properties Of Solids And Liquids Question 453

Properties Of Solids And Liquids Question 453

Question: A body cools from $50.0^{\circ} C$ to $49.9^{\circ} C$ in 5s. How long will it take to cool from $40.0^{\circ} C$ to $39.9^{\circ} C$ ? Assume the temperature of surroundings to be $30.0^{\circ} C$ and Newton’s law of cooling to be valid

Options:

A) 2.5 s

B) 10 s

C) 20 s

D) 5 s

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $\frac{50 - 49.9}{t} = K (\frac{50 + 49.9}{2} - 30)$ ….(i)

$\frac{40 - 39.9}{t} = K [\frac{40 + 39.9}{2} - 30]$ -(ii)

From equations (i) and (ii), we get $t \approx 10 s$ .

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Properties Of Solids And Liquids Question 453

Question: A body cools from 50.0∘C to 49.9∘C in 5s. How long will it take to cool from 40.0∘C to39.9∘C ? Assume the temperature of surroundings to be 30.0∘C and Newton’s law of cooling to be valid

Options:

Answer:

Solution:

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Question: A body cools from $50.0^{\circ} C$ to $49.9^{\circ} C$ in 5s. How long will it take to cool from $40.0^{\circ} C$ to $39.9^{\circ} C$ ? Assume the temperature of surroundings to be $30.0^{\circ} C$ and Newton’s law of cooling to be valid