Properties Of Solids And Liquids Question 450
Question: An experiment takes 10 minutes to raise the temperature of water in a container from $ 0{}^\circ C $ to $ 100{}^\circ C $ and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be$ 1 cal/g{}^\circ C $ , the heat of vapourisation according to this experiment will come out to be :
Options:
A) 560 cal/g
B) 550 cal/g
C) 540 cal/g
D) 530 cal/g
Show Answer
Answer:
Correct Answer: B
Solution:
[b] As $ Pt=mC\Delta T $ So, $ P\times 10\times 60 = mC 100 $ …(i) and $ P\times 55\times 60 = mL $ …(ii) Dividing equation (i) by (ii) we get $ (\theta -{\theta _{0}}) $
$ \therefore L = 550 cal./g. $
