Properties Of Solids And Liquids Question 446
Question: 300 gm of water at $ 25{}^\circ C $ is added to 100 g of ice at$ 0{}^\circ C $ . The final temperature of the mixture is
Options:
A) $ -\frac{5}{3}{}^\circ \text{C} $
B) $ -\frac{5}{2}{}^\circ C $
C) $ 5{}^\circ C $
D) $ 0{}^\circ C $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ {\theta _{mix}}=\frac{m _{W}{\theta _{W}}-\frac{m _{i}L _{i}}{S _{W}}}{m _{i}+m _{W}} $
$ =\frac{300\times 25-\frac{100\times 80}{1}}{100+300}=-1.25{}^\circ C $ Which is not possible. Hence $ {\theta _{mix}} = 0{}^\circ C $
