SATHEE: Properties Of Solids And Liquids Question 440

Properties Of Solids And Liquids Question 440

Question: The rectangular surface of area $8 c m \times 4 c m$ of a black body at temperature $127^{\circ} C$ emits energy E per second. If the length and breadth are reduced to half of the initial value and the temperature is raised to $327^{\circ} C$ , the rate of emission of energy becomes

Options:

A) $\frac{3}{8} E$

B) $\frac{81}{16} E$

C) $\frac{9}{16} E$

D) $\frac{81}{64} E$

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Answer:

Correct Answer: D

Solution:

[d] $E = σ \times a r e a \times T^{4}$ ;

T increases by a factor $\frac{3}{2}$ .

Area increases by a factor $\frac{1}{4}$ .

$\Rightarrow E^{'} \frac{1}{4} \times {(\frac{3}{2})}^{4} \times E = \frac{81}{64} E$

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Properties Of Solids And Liquids Question 440

Question: The rectangular surface of area 8cm×4cm of a black body at temperature 127∘C emits energy E per second. If the length and breadth are reduced to half of the initial value and the temperature is raised to 327∘C , the rate of emission of energy becomes

Options:

Answer:

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Question: The rectangular surface of area $8 c m \times 4 c m$ of a black body at temperature $127^{\circ} C$ emits energy E per second. If the length and breadth are reduced to half of the initial value and the temperature is raised to $327^{\circ} C$ , the rate of emission of energy becomes