SATHEE: Properties Of Solids And Liquids Question 438

Properties Of Solids And Liquids Question 438

Question: A cylindrical rod of aluminum is of length 20 cm, and radius 2 cm. The two ends are maintained at temperatures of $0^{\circ} C$ and $50^{\circ} C$ [the coefficient of thermal conductivity is $\frac{0.5 c a l}{c m \times s e c \times^{o} C}$ ]Then the thermal resistance of the rod in $\frac{c a l}{s e c \times^{o} C}$

Options:

A) 318

B) 31.8

C) 3.18

D) 0.318

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Thermal resistance $R = / l K A$

Where r =20cm. & A(cylindrical rod) $= π r^{2} = 40 π c m^{2}$

So $R = \frac{20}{0.5 \times 40 π} = 0.318 \frac{c a l}{\sec \times^{\circ} C}$

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Properties Of Solids And Liquids Question 438

Question: A cylindrical rod of aluminum is of length 20 cm, and radius 2 cm. The two ends are maintained at temperatures of 0∘C and 50∘C [the coefficient of thermal conductivity is 0.5calcm×sec×oC ]Then the thermal resistance of the rod in calsec×oC

Options:

Answer:

Solution:

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