SATHEE: Properties Of Solids And Liquids Question 436

Properties Of Solids And Liquids Question 436

Question: A kettle with 3 liter water at $27^{\circ} C$ is heated by operating coil heater of power 2 kW. The heat is lost to the atmosphere at constant rate 130 J/sec, when its lid is open. In how much time will water heated to $97^{\circ} C$ with the lid open? (specific heat of water =4.2kJ/kg)

Options:

A) 472 sec

B) 693 sec

C) 912 sec

D) 1101 sec

Show Answer

Answer:

Correct Answer: A

Solution:

[a] By the law of conservation of energy, energy given by heater must be equal to the sum of energy gained by water and energy lost from the lid. $P t = m s Δ θ + e n e r g y l o s t$

$2000 t = 3 \times 4.2 \times 10^{3} \times (97 - 27) + 130 t$

$\Rightarrow t = 472 s e c$

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Properties Of Solids And Liquids Question 436

Question: A kettle with 3 liter water at 27∘C is heated by operating coil heater of power 2 kW. The heat is lost to the atmosphere at constant rate 130 J/sec, when its lid is open. In how much time will water heated to 97∘C with the lid open? (specific heat of water =4.2kJ/kg)

Options:

Answer:

Solution:

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Question: A kettle with 3 liter water at $27^{\circ} C$ is heated by operating coil heater of power 2 kW. The heat is lost to the atmosphere at constant rate 130 J/sec, when its lid is open. In how much time will water heated to $97^{\circ} C$ with the lid open? (specific heat of water =4.2kJ/kg)