SATHEE: Properties Of Solids And Liquids Question 433

Properties Of Solids And Liquids Question 433

Question: A 2 kg copper block is heated to $500^{\circ} C$ and then it is placed on a large block of ice at $0^{\circ} C$ . If the specific heat capacity of copper is $400 J / k g^{\circ} C$ and latent heat of fusion of water is $3.5 \times l 0^{5} J /$ kg, the amount of ice that can melt is

Options:

A) (7/8) kg

B) (7/5) kg

C) (8/7) kg

D) (5/7) kg

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Answer:

Correct Answer: C

Solution:

[c] Let x kg of ice can melt Using law of Calorimetry, Heat lost by copper = Heat gained by ice $2 \times 400 \times (500 - 0) = x \times 3.5 \times 10^{5}$

or $x = \frac{2 \times 400 \times 500}{3.5 \times 10^{5}} = \frac{8}{7} k g$

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Properties Of Solids And Liquids Question 433

Question: A 2 kg copper block is heated to 500∘C and then it is placed on a large block of ice at 0∘C . If the specific heat capacity of copper is 400J/kg∘C and latent heat of fusion of water is 3.5×l05J/ kg, the amount of ice that can melt is

Options:

Answer:

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Question: A 2 kg copper block is heated to $500^{\circ} C$ and then it is placed on a large block of ice at $0^{\circ} C$ . If the specific heat capacity of copper is $400 J / k g^{\circ} C$ and latent heat of fusion of water is $3.5 \times l 0^{5} J /$ kg, the amount of ice that can melt is