Properties Of Solids And Liquids Question 421

Question: A thin steel ring of inner diameter 40 cm and cross- sectional area 1mm2 , is heated until it easily slides on a rigid cylinder of diameter 40.05 cm. [For steel,α=105/C,Y=200GPa ] When the ring cools down, the tension in the ring will be:

Options:

A) 1000 N

B) 500 N

C) 250 N

D) 100 N

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Δ=π×0.5π×40=1800

T=YΔ×A

=200×109×1800×1×106=250N



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