SATHEE: Properties Of Solids And Liquids Question 412

Properties Of Solids And Liquids Question 412

Question: A pendulum clock loses 12 s a day if the temperature is $40^{\circ} C$ and gains 4 s a day if the temperature is $20^{\circ} C$ . The temperature at which the clock will show correct time, and the co- efficient of linear expansion $(α)$ of the metal of the pendulum shaft are respectively:

Options:

A) $30^{\circ} C; α = 1.85 \times 10^{- 3} /^{\circ} C$

B) $55^{\circ} C; α = 1.85 \times 10^{- 2} /^{\circ} C$

C) $25^{\circ} C; α = 1.85 \times 10^{- 5} /^{\circ} C$

D) $60^{\circ} C; α = 1.85 \times 10^{- 4} /^{\circ} C$

Show Answer

Answer:

Correct Answer: C

Solution:

Time lost / gained per day $= \frac{1}{2} α Δ θ \times 86400$

second $12 = - α (40 - 8) \times 86400$ ….(i) $4 = - α (θ - 20) \times 86400$ ….(ii) On dividing we get, $3 = \frac{40 - θ}{θ - 20}$

$36 - 60 = 40 - θ$

$4 θ = 100 \Rightarrow θ = 25^{\circ} C$

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Properties Of Solids And Liquids Question 412

Question: A pendulum clock loses 12 s a day if the temperature is 40∘C and gains 4 s a day if the temperature is20∘C . The temperature at which the clock will show correct time, and the co- efficient of linear expansion (α) of the metal of the pendulum shaft are respectively:

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu