Properties Of Solids And Liquids Question 404
Question: A glass flask is filled up to a mark with 50 cc of mercury at $ 18{}^\circ C $ . If the flask and contents are heated to $ 38{}^\circ C $ , how much mercury will be above the mark? ($ \alpha $ for glass is $ 9\times {{10}^{-6}}/{}^\circ C $ and coefficient of real expansion of mercury is $ 80\times {{10}^{-6}}/{}^\circ C $ )
Options:
A) 0.85 cc
B) 0.46 cc
C) 0.153cc
D) 0.05 cc
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Due to volume expansion of both mercury and flask, the change in volume of mercury related to flask is given by $ \Delta V=V _{0}[ {\gamma _{L}}-{\gamma _{g}} ]\Delta \theta =V[ {\gamma _{L}}-3{\alpha _{g}} ]\Delta \theta $
$ =50( 180\times {{10}^{-6}}-3\times 9\times {{10}^{-6}} ]( 38-18 ) $
$ =0.153cc $
