SATHEE: Properties Of Solids And Liquids Question 390

Properties Of Solids And Liquids Question 390

Question: If two rods A and B of equal length L, and different areas of cross-section $A_{1}$ and $A_{2}$ have one end each at temperature $T_{1}$ and $T_{2}$ , have equal rates of flow of heat, then

Options:

A) $A_{1} = A_{2}$

B) $\frac{A_{1}}{A_{2}} = \frac{K_{1}}{K_{2}}$

C) $\frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$

D) $K_{1} = K_{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $\frac{Δ Q_{1}}{Δ t} = \frac{Δ Q_{2}}{Δ t}$

$\Rightarrow K_{1} A_{1} \frac{T_{1} - T_{2}}{L_{1}} = K_{2} A_{2} \frac{T_{1} - T_{2}}{L_{2}}$

$(L_{1} = L_{2}) ∴ \frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$

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Properties Of Solids And Liquids Question 390

Question: If two rods A and B of equal length L, and different areas of cross-section A1 andA2 have one end each at temperatureT1 and T2 , have equal rates of flow of heat, then

Options:

Answer:

Solution:

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Question: If two rods A and B of equal length L, and different areas of cross-section $A_{1}$ and $A_{2}$ have one end each at temperature $T_{1}$ and $T_{2}$ , have equal rates of flow of heat, then