Properties Of Solids And Liquids Question 365

Question: In order to float a ring of area 0.04 m2 in a liquid of surface tension 75 N/m, the required surface energy will be [RPMT 2003]

Options:

A) 3 J

B) 6.5 J

C) 1.5 J

D) 4 J

Show Answer

Answer:

Correct Answer: A

Solution:

E=T×ΔA=75×0.04=3J



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक