Properties Of Solids And Liquids Question 365
Question: In order to float a ring of area 0.04 m2 in a liquid of surface tension 75 N/m, the required surface energy will be [RPMT 2003]
Options:
A) 3 J
B) 6.5 J
C) 1.5 J
D) 4 J
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=T\times \Delta A=75\times 0.04=3J $