Properties Of Solids And Liquids Question 360

Question: A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is 0.465 J/m2 )[UPSEAT 2002]

Options:

A) 23.4μJ

B) 18.5μJ

C) 26.8μJ

D)16.8μJ

Show Answer

Answer:

Correct Answer: A

Solution:

Increase in surface energy or work done in splitting a big drop =4πR2T(n1/31)

W=4π×(2×103)2×0.465(81/31)=23.4 μJ



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