Properties Of Solids And Liquids Question 359

Question: A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 1 mm while still maintaining their parallelism, how much work will have to be done (Surface tension of water =$ 7.2\times {{10}^{-2}}N/m) $ [MP PET 2001]

Options:

A)$ 7.22\times {{10}^{-6}}Joule $

B) $ 1.44\times {{10}^{-5}}Joule $

C) $ 2.88\times {{10}^{-5}}Joule $

D) $ 5.76\times {{10}^{-5}}Joule $

Show Answer

Answer:

Correct Answer: B

Solution:

Increment in area of soap film = $ A _{2}-A _{1} $

$ =2\times [(10\times 0.6)-(10\times 0.5)]\times {{10}^{-4}}=2\times {{10}^{-4}}m^{2} $

Work done = $ T\times \Delta A $

$ =7.2\times {{10}^{-2}}\times 2\times {{10}^{-4}}=1.44\times {{10}^{-5}}J $



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