SATHEE: Properties Of Solids And Liquids Question 351

Properties Of Solids And Liquids Question 351

Question: The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10-4 joule. The surface tension of the film is[MP PET 1999; JIPMER 2001, 02; MP PMT 2000; AIIMS 2000]

Options:

A) $1.5 \times 10^{- 2} N / m$

B) $3.0 \times 10^{- 2} N / m$

C) $6.0 \times 10^{- 2} N / m$

D) $11.0 \times 10^{- 2} N / m$

Show Answer

Answer:

Correct Answer: B

Solution:

$W = T \times Δ A$ \ $T = \frac{W}{Δ A}$

$T = \frac{3 \times 10^{- 4}}{2 \times (110 - 60) \times 10^{- 4}}$ (Soap film has two surfaces)= $3 \times 10^{- 2} N / m$

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Properties Of Solids And Liquids Question 351

Question: The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10-4 joule. The surface tension of the film is[MP PET 1999; JIPMER 2001, 02; MP PMT 2000; AIIMS 2000]

Options:

Answer:

Solution:

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