Properties Of Solids And Liquids Question 351

Question: The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10-4 joule. The surface tension of the film is[MP PET 1999; JIPMER 2001, 02; MP PMT 2000; AIIMS 2000]

Options:

A) $ 1.5\times {{10}^{-2}}N/m $

B) $ 3.0\times {{10}^{-2}}N/m $

C) $ 6.0\times {{10}^{-2}}N/m $

D) $ 11.0\times {{10}^{-2}}N/m $

Show Answer

Answer:

Correct Answer: B

Solution:

$ W=T\times \Delta A $ \ $ T=\frac{W}{\Delta A} $

$ T=\frac{3\times {{10}^{-4}}}{2\times (110-60)\times {{10}^{-4}}} $ (Soap film has two surfaces)=$ 3\times {{10}^{-2}}N/m $



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