Properties Of Solids And Liquids Question 338

Question: If work W is done in blowing a bubble of radius R from a soap solution, then the work done in blowing a bubble of radius 2R from the same solution is [MP PET 1990]

Options:

A) W/2

B)2W

C) 4W

D)$ 2\frac{1}{3} $ W

Show Answer

Answer:

Correct Answer: C

Solution:

$ W=8\pi R^{2}T $ \ $ W\propto R^{2} $ (T is constant) If radius becomes double then work done will become four times.



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