Properties Of Solids And Liquids Question 332

Question: Work done in splitting a drop of water of 1 mm radius into 106 droplets is (Surface tension of water $ =72\times {{10}^{-3}}J/m^{2}) $ [MP PET/PMT 1988; CPMT 1989; RPET 2001]

Options:

A) $ 9.58\times {{10}^{-5}}J $

B) $ 8.95\times {{10}^{-5}}J $

C) $ 5.89\times {{10}^{-5}}J $

D)$ 5.98\times {{10}^{-6}}J $

Show Answer

Answer:

Correct Answer: B

Solution:

Work done in splitting a water drop of radius R into n drops of equal size$ =4\pi R^{2}T({{n}^{1/3}}-1) $

$ =4\pi \times {{({{10}^{-3}})}^{2}}\times 72\times {{10}^{-3}}\times ({{10}^{6/3}}-1) $

$ =4\pi \times {{10}^{-6}}\times 72\times {{10}^{-3}}\times 99=8.95\times {{10}^{-5}}J $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक