Properties Of Solids And Liquids Question 316

Question: The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is [AMU 1995]

Options:

A) 5 m

B)10 m

C) 15 m

D)20 m

Show Answer

Answer:

Correct Answer: C

Solution:

P1V1=P2V2

therefore (HHgρHg+HWρW)V=HHgρHg×3V

therefore HHgρHg+HWρHg10=3HHgρHg

thereforeHW=2HHg×10

=2×75×10100=15m



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