Properties Of Solids And Liquids Question 302
Question: With rise in temperature, density of a given body changes according to one of the following relations
Options:
A)$ \rho ={\rho _{0}}[1+\gamma d\theta ] $
B)$ \rho ={\rho _{0}}[1-\gamma d\theta ] $
C)$ \rho ={\rho _{0}}\gamma d\theta $
D)$ \rho ={\rho _{0}}/\gamma d\theta $
Show Answer
Answer:
Correct Answer: B
Solution:
Since, with increase in temperature, volume of given body increases, while mass remains constant so that density will decrease. i.e. $ \frac{\rho }{{\rho _{0}}}=\frac{m/V}{m/V _{0}}=\frac{V _{0}}{V}=\frac{V _{0}}{V _{0}(1+r\Delta \theta )}=(1-\gamma \Delta \theta ) $
$ \rho ={\rho _{0}}(1-\gamma \Delta \theta ) $
