Properties Of Solids And Liquids Question 290
Question: The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is[AMU 1995]
Options:
A)5 m
B)10 m
C)15 m
D)20 m
Show Answer
Answer:
Correct Answer: C
Solution:
$ P _{1}V _{1}=P _{2}V _{2} $
therefore $ (P _{0}+h\rho g)V $ =$ P _{0}\times \frac{4}{3}\pi {{(2r)}^{3}} $
therefore $ h\rho g=2P _{0} $
therefore $ h=\frac{2\times 75\times 13.6\times g}{\frac{13.6}{10}\times g} $ = 15 m
