SATHEE: Properties Of Solids And Liquids Question 281

Properties Of Solids And Liquids Question 281

Question: Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9 g / cm3. If the mass of the other is 48 g, its density in g / cm3 is [CBSE PMT 1994]

Options:

A) $\frac{4}{3}$

B) $\frac{3}{2}$

C)3

D)5

Show Answer

Answer:

Correct Answer: C

Solution:

Apparent weight $= V (ρ - σ) g = \frac{m}{ρ} (ρ - σ) g$

where $m =$ mass of the body, $ρ =$ density of the body

$σ =$ density of water

If two bodies are in equilibrium then their apparent weight must be equal.

$∴$ $\frac{m_{1}}{ρ_{1}} (ρ_{1} - σ) = \frac{m_{2}}{ρ_{2}} (ρ_{2} - σ)$

therefore $\frac{36}{9} (9 - 1) = \frac{48}{ρ_{2}} (ρ_{2} - 1)$ By solving we get $ρ_{2} = 3$ .

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Properties Of Solids And Liquids Question 281

Question: Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9 g / cm3. If the mass of the other is 48 g, its density in g / cm3 is [CBSE PMT 1994]

Options:

Answer:

Solution:

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