Properties Of Solids And Liquids Question 247

Question: A soap bubble of radius R is blown. After heating the solution a second bubble of radius 2R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is

Options:

A) Double

B)Slightly less than double

C)Slightly less than four times

D)Slightly more than four times

Show Answer

Answer:

Correct Answer: C

Solution:

[c] work done to form a bubble of radius R $ W _{1}=8\pi R^{2}T _{1} $ .

Work done to form a bubble of radius 2R $ W _{2}=8\pi {{(2R)}^{2}}T _{2}=32\pi R^{2}T _{2}$

$\therefore \frac{W _{1}}{W _{2}}=\frac{T _{1}}{4T _{2}} $ .

If surface tension of soap solution is same, then $ W _{2}=4W _{1} $ .

But in the problem the temperature of solution is increased, so its surface tension decreases. $ \therefore W _{2}<4W _{1} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक