Properties Of Solids And Liquids Question 239
Question: Two capillary of length L and 2L and of radius R and 2R are connected in series. The net rate of flow of fluid through them will be (given rate of the flow through single capillary, $ X=\pi PR^{4}/8\eta L) $ [DCE 2005]
Options:
A)3 m/s
B)6 m/s
C)12 m/s
D)8 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
$ a _{1}v _{1}=a _{2}v _{2} $
therefore $ \frac{v _{2}}{v _{1}}=\frac{a _{1}}{a _{2}}={{\left( \frac{r _{1}}{r _{2}} \right)}^{2}} $
therefore $ v _{2}=3\times {{(2)}^{2}} $ = 12 m/s
