Physics And Measurement Question 87
Question: $ {\mu _{0}} $ and $ {\varepsilon _{0}} $ denote the permeability and permittivity of free space, the dimensions of $ {\mu _{0}}{\varepsilon _{0}} $ are
Options:
A) $ L{{T}^{-1}} $
B) $ {{L}^{-2}}T^{2} $
C) $ {{M}^{-1}}{{L}^{-3}}Q^{2}T^{2} $
D) $ {{M}^{-1}}{{L}^{-3}}I^{2}T^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ C=\frac{1}{\sqrt{{\mu _{0}}{\varepsilon _{0}}}} $
therefore $ {\mu _{0}}{\varepsilon _{0}}=( \frac{1}{C^{2}} ) $ (where C = velocity of light)
$ [{\mu _{0}}{\varepsilon _{0}}]={{L}^{-2}}T^{2} $
