SATHEE: Physics And Measurement Question 81

Physics And Measurement Question 81

Question: The velocity of a freely falling body changes as $g^{p} h^{q}$ where g is acceleration due to gravity and $h$ is the height. The values of $p$ and $q$ are

[NCERT 1983; EAMCET 1994]

Options:

A) $1, \frac{1}{2}$

B) $M^{0} L^{2} T^{- 2}$

C) $\frac{1}{2}, 1$

D) $1, 1$

Show Answer

Answer:

Correct Answer: B

Solution:

$v \propto g^{p} h^{q}$ (given)

By substituting the dimension of each quantity and comparing the powers in both sides we get $[L T^{- 1}] = {[L T^{- 2}]}^{p} {[L]}^{q}$
$\Rightarrow$

$p + q = 1, - 2 p = - 1, ∴ p = \frac{1}{2}, q = \frac{1}{2}$

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अगला

Physics And Measurement Question 81

Question: The velocity of a freely falling body changes as $g^{p} h^{q}$ where g is acceleration due to gravity and $h$ is the height. The values of $p$ and $q$ are

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Physics And Measurement Question 81

Question: The velocity of a freely falling body changes as gphq where g is acceleration due to gravity and h is the height. The values of p and q are

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The velocity of a freely falling body changes as $g^{p} h^{q}$ where g is acceleration due to gravity and $h$ is the height. The values of $p$ and $q$ are