Physics And Measurement Question 69

Question: The dimensions of Farad are

[MP PET 1993]

Options:

A) $ {{M}^{-1}}{{L}^{-2}}T^{2}Q^{2} $

B) $ {{M}^{-1}}{{L}^{-2}}TQ $

C) $ {{M}^{-1}}{{L}^{-2}}{{T}^{-2}}Q $

D) $ {{M}^{-1}}{{L}^{-2}}TQ^{2} $

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Answer:

Correct Answer: A

Solution:

Farad is the unit of capacitance and $ C=\frac{Q}{V} $ = $ \frac{[Q]}{[ML^{2}{{T}^{-2}}{{Q}^{-1}}]} $ = $ {{M}^{-1}}{{L}^{-2}}T^{2}Q^{2} $



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