Physics And Measurement Question 51
Question: The dimensions of power are
[CPMT 1974, 75; SCRA 1989]
Options:
A) $ M^{1}L^{2}{{T}^{-3}} $
B) $ M^{2}L^{1}{{T}^{-2}} $
C) $ M^{1}L^{2}{{T}^{-1}} $
D) $ M^{1}L^{1}{{T}^{-2}} $
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Answer:
Correct Answer: A
Solution:
Power = $ \frac{\text{Work done}}{Time}=[ \frac{ML^{2}{{T}^{-2}}}{T} ]=[ML^{2}{{T}^{-3}}] $