Physics And Measurement Question 51

Question: The dimensions of power are

[CPMT 1974, 75; SCRA 1989]

Options:

A) $ M^{1}L^{2}{{T}^{-3}} $

B) $ M^{2}L^{1}{{T}^{-2}} $

C) $ M^{1}L^{2}{{T}^{-1}} $

D) $ M^{1}L^{1}{{T}^{-2}} $

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Answer:

Correct Answer: A

Solution:

Power = $ \frac{\text{Work done}}{Time}=[ \frac{ML^{2}{{T}^{-2}}}{T} ]=[ML^{2}{{T}^{-3}}] $



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