Physics And Measurement Question 367
Question: SI unit of permittivity is
[KCET 2004]
Options:
A) $ C^{2}m^{2}{{N}^{-1}} $
B) $ {{C}^{-1}}m^{2}{{N}^{-2}} $
C) $ C^{2}m^{2}N^{2} $
D) $ C^{2}{{m}^{-2}}{{N}^{-1}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ F=\frac{1}{4\pi \in }\frac{q _{1}q _{2}}{r^{2}}\Rightarrow \in =\frac{1}{4\pi }\frac{q _{1}q _{2}}{Fr^{2}}=C^{2}{{m}^{-2}}{{N}^{-1}} $
