Physics And Measurement Question 316

Question: The unit of Stefan’s constant $ \sigma $ is

[ MP PMT 1992; CBSE PMT 2002]

Options:

A) $ W{{m}^{-2}}{{K}^{-1}} $ .

B) $ Wm^{2}{{K}^{-4}} $

C) $ W{{m}^{-2}}{{K}^{-4}} $

D) $ W{{m}^{-2}}K^{4} $

Show Answer

Answer:

Correct Answer: C

Solution:

Stefan’s law is $ E=\sigma (T^{4}) $

therefore $ \sigma =\frac{E}{T^{4}} $ where, $ E= $ $ \frac{Energy}{Area\times Time} $ $ =\frac{Watt}{{{m}^{2}}} $

$ \sigma =\frac{\text{Watt-}{{m}^{-2}}}{K^{4}}=Watt-{{m}^{-2}}{{K}^{-4}} $



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