A) $ ohm/m^{2} $
B) $ ohm/m^{3} $
C) $ ohm-m $
D) $ ohm/m $
Correct Answer: C
[c] $ R=\rho \frac{l}{A}\therefore \rho =\frac{RA}{l}=\frac{\Omega m^{2}}{m}=\Omega m $
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