Physics And Measurement Question 211

Question: The pitch and the number of circular scale divisions in a screw gauge with least count 0.02 mm are respectively

Options:

A) 1mm and 100

B) 0.5 mm and 50

C) 1 mm and 50

D) 0.5 mm and 100

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Least count of a screw gauge

$ =\frac{Pitch}{Numberofcircularscaledivisions} $

$ =\frac{1mm}{50}=0.02mm $

Therefore the pitch and no. of circular scale divisions are 1mm and 50 respectively.



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक