Physics And Measurement Question 182

Question: If there is a positive error of 50% in the measurement of velocity of a body, then the error in the measurement of kinetic energy is

Options:

A) 25%

B) 50%

C) 100%

D) 125%

Show Answer

Answer:

Correct Answer: D

Solution:

Kinetic energy $ E=\frac{1}{2}mv^{2} $

$ \therefore \frac{\Delta E}{E}\times 100=\frac{{{{{v}’}}^{2}}-v^{2}}{v^{2}}\times 100 $

$ =[{{(1.5)}^{2}}-1]\times 100 $

$ \therefore \frac{\Delta E}{E}\times 100=125$ %



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