SATHEE: Physics And Measurement Question 164

Physics And Measurement Question 164

Question: The period of oscillation of a simple pendulum is given by $T = 2 π \sqrt{\frac{l}{g}}$ where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is

Options:

A) 0.1%

B) 1%

C) 0.2%

D) 0.8%

Show Answer

Answer:

Correct Answer: C

Solution:

$T = 2 π \sqrt{l / g}$

$\Rightarrow T^{2} = 4 π^{2} l / g$

$\Rightarrow g = \frac{4 π^{2} l}{T^{2}}$

Here % error in l = $\frac{1 m m}{100 c m} \times 100 = \frac{0.1}{100} \times 100 = 0.1$

and % error in T = $\frac{0.1}{2 \times 100} \times 100 = 0.05$

% error in g = % error in l + 2(% error in T)

$= 0.1 + 2 \times 0.05$ = 0.2 %

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Physics And Measurement Question 164

Question: The period of oscillation of a simple pendulum is given by $T = 2 π \sqrt{\frac{l}{g}}$ where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Physics And Measurement Question 164

Question: The period of oscillation of a simple pendulum is given by T=2πlg where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The period of oscillation of a simple pendulum is given by $T = 2 π \sqrt{\frac{l}{g}}$ where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is