Physics And Measurement Question 126
Question: Dimension of electric current is
[CBSE PMT 2000]
Options:
A) $ [M^{0}L^{0}{{T}^{-1}}Q] $
B) $ [ML^{2}{{T}^{-1}}Q] $
C) $ [M^{2}L{{T}^{-1}}Q] $
D) $ [M^{2}L^{2}{{T}^{-1}}Q] $
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Answer:
Correct Answer: A
Solution:
$ I=\frac{Q}{t}=\frac{[Q]}{[T]}=[M^{0}L^{0}{{T}^{-1}}Q] $