SATHEE: Physics And Measurement Question 124

Physics And Measurement Question 124

Question: If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is

[AMU (Med.) 2000]

Options:

A) $T = k \sqrt{ρ r^{3} / S}$

B) $T = k \sqrt{ρ^{1 / 2} r^{3} / S}$

C) $T = k \sqrt{ρ r^{3} / S^{1 / 2}}$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Let $T \propto S^{x} r^{y} ρ^{z}$

by substituting the dimension of $[T] = [T]$

$[S] = [M T^{- 2}], [r] = [L], [ρ] = [M L^{- 3}]$

and by comparing the power of both the sides $x = - 1 / 2, y = 3 / 2, z = 1 / 2$

so $T \propto \sqrt{ρ r^{3} / S} \Rightarrow T = k \sqrt{\frac{ρ r^{3}}{S}}$

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Physics And Measurement Question 124

Question: If the time period (T) of vibration of a liquid drop depends on surface tension (S) , radius (r) of the drop and density (ρ) of the liquid, then the expression of T is

Options:

Answer:

Solution:

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Question: If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is